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AN6535 4-pin Negative Adjustable Voltage Regulator s Overview The AN6535 is a monolithic 4-pin negative adjustable voltage regulator. With an external resistor, it provides any stabilized output voltages between -5V and-30V, and is optimum for the power circuits with a current capacitance of up to 0.5A. With various protective circuits built in, it has high reliability and is provided in a 4-lead SIL plastic package. 9.6 - 0.1 o 3.1 4.0 + 0.5 Unit:mm 12.5max. 0.70.2 9.0min. 3-1.0 1.8 2.0 0.50.1 1.5 1.3 s Features * Wide range of output voltages:VO= -5 to -30V * Interal thermal overload protection * Interal short-circuit protection * Output transistor safe area compensation 2.3 2.3 2.3 3.3max. 4-pin SIL Plastic Package with Fin (SSIP004-P-0000) s Block Diagram Start Circuit Ref. Voltage + Error Amp. - Output Pass Tr. Thermal Protection Rsc Short Circuit Protection 1 Common 2 Input 3 Output 4 Control s Absolute Maximum Ratings (Ta=25C) Parameter Supply voltage Supply current Power dissipation Operating ambient temperature Storage Symbol VCC ICC *1 PD Topr Tstg Rating -40 1 7.5 -20 to +80 -55 to +150 Unit V A W C C *1 The internal circuit is provided with a current limiting circuit. *2 Maximum power dissipation value when there is no heat sink (The value varies depending on the external heat dissipation state) s Electrical Characteristics (Ta=25C) Parameter Output voltage tolerance Symbol VO Condition VI=VO-3V to VO-15V, IO=5 to 350mA, Tj=25C VO=-5V, IO=200mA, VI=-7.5 to -25V, Tj=25C VO=-18V, IO=5mA, VI=-21 to -33V, Tj=25C VO=-18V, IO=200mA, VI=-21 to -25V, Tj=25C IO=5 to 500mA Tj=25C Tj=25C Tj=25C VI=-8 to -18V, VO=-5V, f=120Hz VO=-5V, f=10Hz to 100kHz IO=500mA, Tj=25C VI=-35V, VO=-5V, Tj=25C VO=-5V, Tj=25C VO=-5V IO=5mA Tj=25C Tj=-20 to +25C Tj=25 to 150C -3.12 0.4 VO=-5V, VI=-12V VO=-18V, VI=-25V 1.5 min typ max 4 1 0.75 0.67 1 3 3 60 40 1.1 100 0.8 0.2 - 0.3 -3 -2.88 600 1.4 Unit % % % % % mA A dB V V mA A mV/C V Line regulation REGIN Load regulation Bias current Control pin current Ripple rejection ratio Output noise voltage Minimum input/output voltage difference Short-circuit current Peak output current Output voltage temperatrue coefficient Control pin voltage REGL IBias Icont RR Vno VDIF (min.) IOS IOP VO/Ta Vcont Note 1) The specified condition Tj=25C means that the test should be conducted with each test time reduced (within 10 ms) so that the drift in the characteristic value due to a temperature rise at chip junction can be ignored. Note 2) Unless otherwise specified, VI=-10V, VO=-5V, IO=350mA, CI=2F, and CO=1F s Characteristics Curve PD -Ta 10 (1) (2) (3) (4) (1) 6 (2) 4 (3) 2 (4) 0 0 20 40 60 80 100 120 140 160 0 Te=Ta With a 10C/W heat sink With a 20C/W heat sink Without heat sink 1.6 1.4 IOP -VDIF Tj=25C VDIF (min.) -Tj Min. I/O Voltage Difference VDIF (min.) (V) 1.4 Power Dissipation PD (W) 8 Peak Output Current IOP (A) 1.2 IO = IO = 1.2 1.0 0.8 0.6 0.4 0.2 1.0 20 I=500mA 0m A 10 IO= 0.8 0m A 10m A 0.6 0.4 -50 0 50 100 150 10 20 30 Ambient Temperature Ta (C) I/O Voltage Difference VDIF (V) Juction Temperature Tj (C) RR- f 120 IO=100mA Line Transient Response VO=5V -15 Ripple Rejection Ratio RR (dB) 100 Output Voltage Fluctuation (mV) 80 -10 60 -5 10 40 0 20 -10 0 10 100 1k 10k 100k -20 0 2 4 6 8 10 Frequency f (Hz) Time t (s) Load Transient Response Load Current IO (A) Output Voltage VO (V) -6 1 Output Current Limit 104 VI=-10V VO=-5V IO=20mA CO=1F Ta=25C 103 Input Voltage V (V) -20 ZO - f 0.5 -4 Output Voltage Fluctuation (V) 0 1 -3 VI=-10V VO=-5V Tj=25C Output Impedance ZO (m) 0.4 0.6 0.8 1.0 1.2 -5 0 -2 102 -1 -1 -2 0 0 10 20 30 40 50 0 0.2 10 10 100 1k 10k 100k 1M Time t (s) Output Current IO (A) Frequency f (Hz) s Basic Regulator Circuit +VI 2 3 R2 Vcont - + +VO Input Output CI : 2F - + Control 4 Common 1 R1 s Application Circuits (1) Current Boost Circuit VI R3 6 2 IR 2F - + IP Input Output 3 4 3k IO VO R2 - R1 + 1F IR - 2F + R3 6 Q2 2 IP Input Output 3 4 3k R1 VI Q1 RSC Ie2 IO VO R2 - 1F + Ie1 CO 1F AN6535 R1+R2 R1 (Vcont 3V, R1=3k) CI : Necessary when the VI line is long. CO : Improves the transient response. VO=Vcont (2) Current Boost Circuit (With Current Limiting Circuit) Q1 AN6535 Control Common 1 AN6535 Control Common 1 R3= VBE (Q1) * ( +1) IP - IO VBE (Q1) RSC= I e1 (max.) R3= VBE (Q1)+Ie1RSC IO - Ie1 VBE (Q1)+BE (Q1) R3 Ie1 (max.)=IP (max.) - |
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